In this task students investigate and ultimately prove the validity of the method of generating Pythagorean Triples that involves the polynomial identity (x 2 y 2) 2 =(x 2y 2) 2 (2xy) 2 Type ProblemSolving Task I am trying to solve the equation $$ (x^2y^2)y' 2xy = 0 $$ I have rearranged to get $$ y' = f(x,y) $$ where $$ f(x,y) = \frac{2xy}{x^2y^2} $$ From here I tried to use a trick that I learned Stack Exchange Network Stack Exchange network consists of 178 Q&A communities including Stack Overflow,Add − x 2 y 2 x 2 y 2 and x 2 y 2 x 2 y 2 Add x 2 x 2 x 2 x 2 and 0 0 Simplify each term Tap for more steps Multiply x 2 x 2 by x 2 x 2 by adding the exponents Tap for more steps Use the power rule a m a n = a m n a m a n = a m n to combine exponents Add 2 2 and 2 2
Pythagorean Identities Mathbitsnotebook Ccss Math
